Thursday, 18 June 2015

9701 MCQ Solution 11

Question 11: [Physical > Equilibria]:
In an experiment, b mol of hydrogen iodide were put into a sealed vessel under pressure p. At equilibrium, x mol of the hydrogen iodide had dissociated, the reaction being represented by the following equation.
2HI(g) รณ H2(g) + I2(g)
Which expression for Kp is correct?
A (x2)/(b x)2
B (x2p2)/(b x)2
C (x2p2)/(4b)(b x)
D (x2)/4(b x)2
Reference: Past Exam Paper – November 2002 Paper 1 Q11



Solution 11:
Answer: D.
The equation for calculating Kp:
Kp = p(products)/p(reactants)
Equilibrium mols of H2 = 0.5x because of the chemical equation
Equilibrium mols of I2 = 0.5x because of the chemical equation
Equilibrium mols of HI = bx because this will be the mols remaining after reaching equilbrium
p(products) = (0.5x)(0.5x) = 0.25x2
p(reactants) = (bx)2

Therefore Kp = (0.25x2)/ (bx)2 = (x2)/4(b x)2

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